🎯 IIT Roorkee JEE Advanced Cut-off 2024
Program | Opening Rank | Closing Rank |
|---|---|---|
Computer Science and Engineering (B.Tech) | 1 | 88 |
Electrical Engineering (B.Tech) | 29 | 200 |
Mechanical Engineering (B.Tech) | 151 | 950 |
Aerospace Engineering (B.Tech) | 395 | 1100 |
Chemical Engineering (B.Tech) | 450 | 1600 |
Civil Engineering (B.Tech) | 580 | 1700 |
Engineering Physics (B.Tech) | 175 | 1200 |
Metallurgical Engineering and Materials Science (B.Tech) | 1200 | 2200 |
Environmental Science and Engineering (B.Tech) | 1300 | 2300 |
B.S. in Mathematics (Mathematics and Computing) | 90 | 380 |
B.S. in Economics (4-year) | 800 | 1500 |
B.S. in Chemistry | 2200 | 3000 |
B.S. in Physics | 1300 | 2200 |
Dual Degree - Electrical Engineering (B.Tech+M.Tech) | 500 | 1200 |
Dual Degree - Mechanical Engineering (B.Tech + M.Tech) | 900 | 1600 |
Dual Degree - Aerospace Engineering (B.Tech + M.Tech) | 1700 | 2300 |
Dual Degree - Civil Engineering (B.Tech + M.Tech) | 1900 | 2700 |
Dual Degree - Chemical Engineering (B.Tech + M.Tech) | 1500 | 2200 |
Dual Degree - Metallurgical Engineering & Materials Science | 2300 | 3200 |
Factors Influencing Cutoffs 🔍📊
Exam Difficulty: Higher difficulty in JEE Advanced can lead to higher ranks and thus higher cutoffs.
Number of Applicants: A larger number of applicants generally increases the competition and cutoffs.
Seat Availability: Branches with fewer seats may have higher cutoffs due to higher demand.
Previous Year Trends: Cutoffs often follow trends, though they can fluctuate each year.
Reservation Categories: SC, ST, OBC-NCL, and PwD candidates usually have relaxed cutoffs.
Admission Process at IIT Roorkee 📝🎓
Qualify JEE Advanced: Secure a valid rank in JEE Advanced.
Eligibility Criteria: Minimum of 75% in Class XII (65% for SC/ST/PwD) or top 20 percentile in board exams.
JoSAA Counseling: Participate in counseling, including choice filling and seat allocation.
Final Admission: Complete verification and fee payment post seat allocation.